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Mercury(II) iodide (Hg I2) is a chemical compound with an appearance of red-orange crystals. Unlike mercury(II) chloride it is hardly soluble in water (<100 ppm). Conditions/substances to avoid include: heat, light, bromides, chlorides, ammonia, alkalis, cyanides, copper salts, lead salts, iodoform and hydrogen peroxide. Mercury(II) iodide displays thermochromism; when heated above 126 °C, it undergoes phase transition from the alpha crystalline form to a pale yellow beta form. As the sample cools, it gradually reacquires its original color. It is often used for thermochromism demonstrations. Mercury(II) iodide is used for preparation of Nessler's reagent, used for detection of presence of ammonia. Mercury(II) iodide is a semiconductor material, used in some x-ray and gamma ray detection and imaging devices operating at room temperatures. Mercury(II) iodide can be found extremely rarely in nature as mineral coccinite. In medicine, mercury(II) iodide was formerly used as a treatment for syphilis (see Protiodide). In veterinary medicine, mercury(II) iodide is used in blister ointments in exostoses, bursal enlargement, etc. From Wikipedia under the
GNU Free Documentation License Write the correct chemical formulas for each of the following compounds? Q. Copper (I) oxide Copper(II) oxide Mercury(II) chloride Silver flouride Iron (II) selenide Zinc oxide Copper (II) sulfide Iron (III) chloride Zinc Sulfide Mercury (II) iodide correct answers will get best answer. Good Luck! Asked by thisismyhobby - Wed Apr 2 22:20:45 2008 - - 2 Answers - 0 Comments A. Cu2O, CuO, HgCl2, AgF, FeSe, ZnO, CuS, FeCl3, ZnS, HgI2 :) Answered by rubidium.chloride - Wed Apr 2 23:55:40 2008 molarity problem help? Q. Concentrated nitric acid is available as a 16 M solution. What volume of nitric acid must be diluted with distilled water to prepare 3.25 L of 0.40 M HNO3? Given that 24.0 mL of 0.170 M sodium iodide reacts with 0.209 M mercury(II) nitrate solution according to the unbalanced equation given below. Hg(NO3)2(aq) + NaI(aq) HgI2(s) + NaNO3(aq) (a) What volume of Hg(NO3)2 is required for complete precipitation? (b) What is the mass of HgI2 precipitate? Asked by metallica123 - Sun Feb 1 21:15:14 2009 - - 1 Answers - 0 Comments A. For your first one, just think about it as a dilution question You want initial #mol = final #mol To get #mol, just do [HNO3]*volume HNO3 used. Find the #mol equivalent to 3.25L 0.4M HNO3 from 16M. You'll eventually get the #L 16M solution you need and the difference between that #L and your total volume (3.25L) is the #L water you need to add along with it. Same mole ratio kind of idea in the other question. Find #mol NaI reacted and divide that by the [Hg(NO3)2] to get #L Hg(NO3)2 required From there, use mole ratios again along with molecular weights to find #g HgI2 produced. Answered by /\/ ? - Sun Feb 1 22:12:51 2009 Impossible question for Chemistry, it's my last one and idk how to do it!?
Q. Given that 24.0 mL of 0.170 M sodium iodide reacts with 0.209 M mercury(II) nitrate solution according to the unbalanced equation given below. Hg(NO3)2(aq) + NaI(aq) HgI2(s) + NaNO3(aq) (a) What volume of Hg(NO3)2 is required for complete precipitation? (in mL) (b) What is the mass of HgI2 precipitate? (in grams) Asked by suavelos15 - Sat Jan 31 12:23:49 2009 - - 21 Answers - 0 Comments A. balance equation is Hg(NO3)2(aq) + 2NaI(aq) HgI2(s) + 2NaNO3(aq) a) Acc to molarity eq. M1V1/n1 = M2V2/n2 0.170 * 24.0 / 2 = 0.209 * V2/ 1 now u can calculate V2. (b) Molar mass of NaI = 23+127 =160 amu Molarity = no of moles of NaI/vol of soln in ml *1000 0.170 = n/24 *1000 and n= w/Molar mass = w/160 or 0.170 = w/160/24 *1000 = let 'x' g now, calculate molar mass of HgI2 say = 'y' g from balance equation 2*160 g of NaI gives 'y' g of HgI2 1 g of NaI gives y/320 g of HgI2 'x' g of NaI gives y/320 * x g of HgI2 no u can calculate the ans. Answered by sona - Sat Jan 31 12:46:43 2009 From Yahoo Answer Search: "Mercury(II) iodide"  news.google.com Washington Post Same with trace amounts of flouride, iodine , copper, cobalt, etc. People living in some of the most radioactive areas or with high mercury levels, ... and more » From Google News Search: "Mercury(II) iodide"  jchemed.chem.wisc.edu:8000 240px x 320px | 8.50kB [source page] sodium iodide and mercury II chloride Last Frame From Yahoo Image Search: "Mercury(II) iodide"  autismdiva.blogspot.com Autism Diva ue, 28 Feb 2006 06:21:00 GM Gold .. 2. mg, Silver . 2. mg. For comparison you probably have 2300 mg of zinc, 320 mg of strontium, 120 mg of lead, 72 mg of copper, 50 mg of cadmium, 20 of . iodine. , 15 mg each of nickel and selenium, 12 mg of manganese and 7 of arsenic. ...  natmedtalk.com Harry Hirsute Mon, 24 Nov 2008 08:00:00 GM My understanding is that selenium really is necessary and helpful to . iodine. therapy; however, it should be taken about . 2. hours away from . iodine. . The same for vitamin C and other antioxidants; but especially vitamin C. Selenium is a very powerful antioxidant. . ... In scientific jargon, selenium has an unusually high "binding affinity" for . mercury. . In layman's terms, this means that when the two elements are found together, they tend to connect, forming a new substance. ...  badatsports.com Admin Sun, 18 Mar 2007 16:45:42 GM Meth labs can also give off noxious fumes, such as phosphine gas, . mercury. vapors, lead, methylamine gas, solvent fumes; such as acetone or chloroform, . iodine. vapors, white phosphorus, anhydrous ammonia, hydrogen chloride/muriatic acid, ... From Google Blog Search: "Mercury(II) iodide" |
